Solved basic word problems on sets:
1. Let A and B be two finite sets such that n(A) = 20, n(B) = 28 and n(A ∪ B) = 36, find n(A ∩ B).
Solution:
Using the formula n(A ∪ B) = n(A) + n(B) – n(A ∩ B).
then n(A ∩ B) = n(A) + n(B) – n(A ∪ B)
= 20 + 28 – 36
= 48 – 36
= 12
2. If n(A – B) = 18, n(A ∪ B) = 70 and n(A ∩ B) = 25, then find n(B).
Solution:
Using the formula n(A∪B) = n(A – B) + n(A ∩ B) + n(B – A)
70 = 18 + 25 + n(B – A)
70 = 43 + n(B – A)
n(B – A) = 70 – 43
n(B – A) = 27
Now n(B) = n(A ∩ B) + n(B – A)
= 25 + 27
= 52
Probality
2. A survey of 200families shows the results given below:
No. of girls in the family | 2 | 1 | 0 |
---|---|---|---|
No. of Families | 32 | 154 | 14 |
Out of these families, one is chosen at random. What is the probability that the chosen family has 1 girl?
Solution:
Total number of families = 200.
Number of families having 1 girl = 154.Probability of getting a family having 1 girl
= Number of families having 1 girl/Total number of families
= 154/200
= 77/100
A dice is thrown 65 times and 4 appeared 21 times. Now, in a random throw of a dice, what is the probability of getting a 4?
Solution:
Total number of tria1s = 65.Number of times 4 appeared = 21.Probability of getting a 4 = Number of times 4 appeared/Total number of trials
= 21/65